### Scribe's Sililoquy

So today in class Mr. K layed out exactly what he wanted to get done. It seemed that division was the "theme" of the day. So first there was the review of last class and grade 5 and 10 division which would be the topic for the class. He gave us the following problems:

Then after we had finished those he asked us if we could see a pattern in relation to the P(-2) for a), P(1) for c) and a P(3) for c) of the numerator of each of those functions that he gave to us and the remainder. Then Craig (of course) had found it and told us, it seems that the answer that was in the numerator after the evaluation had been complete was the remainder! Now we needed a bit more information on how this happens and Mr. K obliged us. It seemed that after a bundle of explaining if you take the root of the denominator and put it in the numerator of the division question and solve you will get your remainder. I don't know if I explained it well but it will have to suffice as my explanation. That would be the Remainder Theorem.

Well I was thinking... "And the use of this is...?" He then went onto explaining his point with the grade 5 problem. The answer to the problem is 718. It takes 3 of those to give you 2154. Well those two numbers they are factors of 2154. Well that also works with polynomials. If it divides evenly then you have factors of that polynomial (no remainder). Which can be useful I guess. That would be the Factor Theorem.

Well we never did get to the Grade 11 way of doing the division but that will be done tomorrow and the scribe for that will be

.... *Drumroll*.........

## 1 Comments:

An excellent scribe! Great use of colour and graphics.

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