<body><script type="text/javascript"> function setAttributeOnload(object, attribute, val) { if(window.addEventListener) { window.addEventListener('load', function(){ object[attribute] = val; }, false); } else { window.attachEvent('onload', function(){ object[attribute] = val; }); } } </script> <div id="navbar-iframe-container"></div> <script type="text/javascript" src="https://apis.google.com/js/platform.js"></script> <script type="text/javascript"> gapi.load("gapi.iframes:gapi.iframes.style.bubble", function() { if (gapi.iframes && gapi.iframes.getContext) { gapi.iframes.getContext().openChild({ url: 'https://www.blogger.com/navbar.g?targetBlogID\x3d14084555\x26blogName\x3dPre-Cal+30S\x26publishMode\x3dPUBLISH_MODE_BLOGSPOT\x26navbarType\x3dBLUE\x26layoutType\x3dCLASSIC\x26searchRoot\x3dhttps://pc30s.blogspot.com/search\x26blogLocale\x3den_US\x26v\x3d2\x26homepageUrl\x3dhttp://pc30s.blogspot.com/\x26vt\x3d8208731429403650487', where: document.getElementById("navbar-iframe-container"), id: "navbar-iframe" }); } }); </script>

Monday, October 03, 2005

The Muddiest Point!

Test day is Wednesday. I'm away for the next two days. Use the comments of this post to share with Mr. Tram, my substitute, your personal "Muddiest Point". You can use your name or leave your comment anonymously, but, whatever you do, share your troubles here. Remember, not only can Mr. Tram help you but you can help each other too! Leave tips and advice in the comments for your classmates. And don't forget, you can form an online study group and "meet" in the chatbox of our blog! Unlike Sysiphus, you're being set up to succeed! Take advantage of every opportunity you've got!

15 Comments:

At 10/03/2005 6:31 PM, Anonymous Anonymous said...

im having trouble with interval notation/finding the domain and range/and problem solving.also with angle measures and the unit circles.

 
At 10/03/2005 7:12 PM, Anonymous Anonymous said...

i am having trouble with telling the diffrence between cosine and sine when graphing them .

 
At 10/03/2005 7:39 PM, Anonymous Anonymous said...

I cannot for the life of me draw the diagrams for this unit. I cannot visualize them, and if ya can't visualize them you can't really solve the problems. I understand the concepts though, and once i do have the diagram I can solve the question quickly.

 
At 10/03/2005 8:06 PM, Anonymous Anonymous said...

I am having trouble with problem solving. When I read the question, my mind goes blank. I can only understand it when there's a diagram to help me.

 
At 10/03/2005 8:19 PM, Anonymous Anonymous said...

I'm having trouble with finding related angles because sometimes when I check my answers there are one, two, three or four different ones and sometimes I don't know how they get just one or how you get more than one=S

 
At 10/03/2005 8:22 PM, Anonymous Anonymous said...

I am having trouble with drawing the diagrams. Its way to hard to visualize..:(

 
At 10/03/2005 9:16 PM, Anonymous Anonymous said...

Haha my muddiest point? Hmmm... I guess if any in this unit I think maybe just decifering word problems...

 
At 10/03/2005 9:22 PM, Anonymous Anonymous said...

im having trouble finding the related angle (just like what anonymous #5 said)...AND graphing the sine and cosine (like what abriel said)

 
At 10/03/2005 9:41 PM, Anonymous Anonymous said...

i'm having a hard time with word problems and i think most of us are.

 
At 10/03/2005 9:57 PM, Anonymous Anonymous said...

i'm having so much trouble working with word problems and having to use trig to solve them

 
At 10/03/2005 11:33 PM, Anonymous Anonymous said...

the thing im having trouble with is what mathemathical formula do I need to use for a specific word problem. theres a lot of formulas in the math world that makes me go crazy.

 
At 10/04/2005 5:17 PM, Anonymous Anonymous said...

I'm having trouble with problem solving and what formulas to use and how to set it up.

 
At 10/04/2005 6:39 PM, Blogger jennie_s said...

muddiest point? geez.. im like in a swamp with some dry patches... im kidding =P. I'm having problems with graphing an equation. i know what everything means just having trouble putting it all together...

 
At 1/09/2007 7:16 AM, Anonymous Anonymous said...

Hi. I have kind of a direct question. heres the problem Im stuck on...
A can in the shape of a right circular cylinder is required to have a volume of 500 cubic centimeters. The top and bottom are made of material that costs 6 per square centimeter, while the sides are made of material that costs 4 per square centimeter.
cans circular part-area is Pie*r^2 and the rectangular area is 2*pie*r*height

(a) Express the total cost C of the material as a function of the radius r of the cylinder.
C(r) =

(b) Graph C = C(r). For what value of r is the cost C least?
cm
can u please help me????????

 
At 1/09/2007 8:51 AM, Blogger Darren Kuropatwa said...

The class that created this blog ended a year ago, in January 2006. In this post the students are leaving questions they have for the substitute teacher they had the next day in class.

Nonetheless, here are a few ideas that may help you out:

(a) The area of the base and side depends on the radius, as you pointed out. The only value you do know is the Volume= 500cm^3.

Recall that the formula for the volume of a cylinder is V=π*r^2*h which means that π*r^2*h = 500 ... can you find the radius from this?

(b) The cost of material for the side is different that that of the base. If you know the area of each of these you could find the different costs of the base and side. The formula would begin:

C(r) = 6*(area of base) + ...

Can you finish this off and put in the correct formulas?

If you need more help you might want to ask Dr. Math.

Cheers!
Mr. Kuropatwa

 

Post a Comment

<< Home